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			<titleStmt><title level='a'>THE BOUNDARY OF THE p -RANK STRATUM OF THE MODULI SPACE OF CYCLIC COVERS OF THE PROJECTIVE LINE</title></titleStmt>
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				<publisher>Cambridge University Press</publisher>
				<date>12/01/2022</date>
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				<bibl> 
					<idno type="par_id">10520606</idno>
					<idno type="doi">10.1017/nmj.2022.12</idno>
					<title level='j'>Nagoya Mathematical Journal</title>
<idno>0027-7630</idno>
<biblScope unit="volume">248</biblScope>
<biblScope unit="issue"></biblScope>					

					<author>EKIN OZMAN</author><author>RACHEL PRIES</author><author>COLIN WEIR</author>
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			<abstract><ab><![CDATA[Abstract. We study the p-rank stratiﬁcation of the moduli space of cyclic degree ! covers of the projective line in characteristic p for distinct primes p and !. The main result is about the intersection of the p-rank 0 stratum with the boundary of the moduli space of curves. When ! = 3 and p ≡ 2 mod 3 is an odd prime, we prove that there exists a smooth trielliptic curve in characteristic p, for every genus g, signature type (r,s), and p-rank f satisfying the clear necessary conditions.]]></ab></abstract>
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<div xmlns="http://www.tei-c.org/ns/1.0"><head>&#167;1. Introduction</head><p>Suppose Y is a smooth projective connected curve of genus g defined over an algebraically closed field k of characteristic p &gt; 0. The p-rank of Y is the integer f such that p f is the number of p-torsion points of the Jacobian of Y. It is known that 0 &#8804; f &#8804; g.</p><p>Let g &#8805; 2. Consider the moduli space M g of smooth curves of genus g over k and its Deligne-Mumford compactification M g . Consider the boundary &#948;M g = M g -M g of M g ; its points represent singular stable curves of genus g.</p><p>It is a compelling problem to understand the geometry of the p-rank f stratum M f g of M g . For example, in most cases, it is not known whether M f g is irreducible. It is known, by <ref type="bibr">[10,</ref><ref type="bibr">Th. 2.3]</ref>, that every irreducible component of M f g has dimension 2g -3 + f . By <ref type="bibr">[4,</ref><ref type="bibr">Lem. 3.2]</ref>, every irreducible component of M f g contains an open dense subset which lies in M f g . It follows that there exists a smooth curve of genus g and p-rank f defined over F p for every prime p and pair of integers g and f such that 0 &#8804; f &#8804; g.</p><p>The proof of <ref type="bibr">[10,</ref><ref type="bibr">Th. 2.3]</ref> uses properties of the intersection of the p-rank strata with the boundary. By <ref type="bibr">[10,</ref><ref type="bibr">Lem. 2.5]</ref> (see also <ref type="bibr">[4,</ref><ref type="bibr">Cor. 3.6]</ref>), every irreducible component S of the p-rank 0 stratum M 0 g intersects &#948;M g ; specifically: (i) S contains points that represent chains of g (supersingular) elliptic curves and (ii) S intersects every irreducible component of &#948;M g . Analogously, for odd p, one can study the p-rank f stratum H f g of the moduli space H g of hyperelliptic curves of genus g. By <ref type="bibr">[11,</ref><ref type="bibr">Prop. 2]</ref>, every irreducible component of H f g has dimension g -1 + f . Every irreducible component of H f g contains an open dense subset which lies in H f g <ref type="bibr">[5,</ref><ref type="bibr">Lem. 3.2]</ref>. It follows that there exists a smooth hyperelliptic curve of genus g and p-rank f defined over F p for every odd prime p and pair of integers g and f such that 0 &#8804; f &#8804; g.</p><p>The proof of these facts for the hyperelliptic locus also uses the intersection of the p-rank strata with the boundary &#948;H g = H g -H g . Every irreducible component S of the p-rank 0 stratum H 0 g intersects &#948;H g by <ref type="bibr">[5,</ref><ref type="bibr">Th. 3.11]</ref>; specifically: (i)' S contains points that represent trees of g (supersingular) elliptic curves. However, it is not known whether S intersects every irreducible component of &#948;H g . In this paper, for an odd prime &#8467; with &#8467; = p, we study analogous questions about the p-ranks of curves that admit a Z/&#8467;Z-cover of the projective line P 1 . Let T &#8467;,g denote the moduli space of such Z/&#8467;Z-covers, and let T &#8467;,g denote its compactification. The irreducible components of T &#8467;,g are indexed not only by the degree &#8467; and the genus g, but also by the discrete data of the inertia type, which determines the signature type. In Proposition 4.1, we compute a lower bound for the dimension of each irreducible component of the p-rank strata of T &#8467;,g , in terms of the signature type.</p><p>The first topic we study is how the p-rank 0 stratum T 0 &#8467;,g of the moduli space T &#8467;,g intersects the boundary &#948;M g . The first main result of the paper is the following theorem. The geometric conclusion from Theorem 1.1 is not as strong as the analogous result in the hyperelliptic case. This prevented us from using Theorem 1.1 to find the dimension of the irreducible components of T f &#8467;,g in general (see Remark 4.4 and  &#167;7.2). For this reason, in &#167;5, we specialize to the case &#8467; = 3. In Proposition 5.9, for all g &#8805; 2 and all primes p &#8805; 5, we generalize a result of Bouw by proving that every component of the moduli space of trielliptic curves of genus g contains a curve whose p-rank is not the maximum. Then we prove the following theorem.</p><p>Theorem 1.2 [See <ref type="bibr">Theorem 5.11]</ref>. For every odd p &#8801; 2 mod 3, every g &#8712; N, every trielliptic signature type (r, s) for g, and every f (satisfying the clear necessary conditions that f is even and 0 &#8804; f &#8804; 2min(r, s)), there exists a smooth trielliptic curve defined over F p with genus g, signature type (r, s), and p-rank f; furthermore, the dimension of at least one irreducible component of the p-rank f stratum of T 3,g,(r,s) equals the lower bound from Proposition 4.1.</p><p>In Corollary 6.4, we strengthen Theorem 1.2 when g is small for all odd primes p &#8801; 2 mod 3 using an application of Theorem 1.1.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>&#167;2. Background</head><p>In this section, we include necessary material about cyclic covers and the p-rank.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="2.1">Stable Z/&#8467;Z-covers of a genus zero curve</head><p>Let k be an algebraically closed field of characteristic p &gt; 0, and let S be an irreducible scheme over k. Let G = Z/&#8467;Z be a cyclic group of odd prime order &#8467; = p. Let G * = G -{0}.</p><p>Let &#968; : Y &#8594; S be a semi-stable curve. If s &#8712; S, let Y s denote the fiber of Y over s. Let Sing S (Y ) be the set of z &#8712; Y for which z is a singular point of the fiber Y &#968;(z) .</p><p>A mark R &#926; on Y /S is a closed subscheme of Y -Sing S (Y ) which is finite and &#233;tale over S. The degree of R &#926; is the number of points in any geometric fiber of R &#926; &#8594; S. A marked semi-stable curve (Y /S, R &#926; ) is stably marked if every geometric fiber of Y satisfies the following condition: for each irreducible component Y 0 of genus zero, #(Y 0 &#8745; (Sing S (Y ) &#8746; R &#926; )) &#8805; 3. (If the fibers of Y /S have genus 1, we also assume that the degree of R &#926; is positive.) Consider a G-action &#953; 0 : Suppose that (Y /S, &#953; 0 ) is an admissible stable G-curve. Then Y /&#953; 0 (G) is also a stably marked curve <ref type="bibr">[8,</ref><ref type="bibr">Prop. 1.4]</ref>. The mark on Y /&#953; 0 (G) is the smooth branch locus B sm , which is the (reduced subscheme of) the image of R sm under the morphism Y &#8594; Y /&#953; 0 (G). Let n be the degree of R sm (the number of smooth ramification points). We suppose from now on that Y /&#953; 0 (G) has arithmetic genus 0. By the Riemann-Hurwitz formula, the arithmetic genus of each fiber of Y is</p><p>(1)</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="2.2">The inertia type and signature type</head><p>Let s be a geometric point of S, and let a be a point of the fiber R sm,s . Then G = Z/&#8467;Z acts on the tangent space of Y s at a via a character &#967; a : G &#8594; k * . In particular, there is a unique choice of &#947; a &#8712; (Z/&#8467;Z) * so that &#967; a (1) = &#950; &#947; a &#8467; . We say that &#947; a is the canonical generator of inertia at a. The inertia type of (Y /S, &#953; 0 ) is the multiset &#947; = {&#947; a | a &#8712; R sm,s }. It is independent of the choice of s. By Riemann's existence theorem, there exists a cover (Y, &#953; 0 ) with inertia type {&#947; a | a &#8712; R sm,s } if and only if a&#8712;R sm,s &#947; a = 0 &#8712; Z/&#8467;Z <ref type="bibr">[24,</ref><ref type="bibr">Th. 2.13]</ref>.</p><p>A labeling of a mark R &#926; of degree n is a bijection &#951; between {1, . . . , n} and the irreducible components of R &#926; . A labeling of an admissible stable G-curve (Y /S, &#953; 0 ) is a labeling &#951; of R sm . There is an induced labeling &#951; 0 : {1, . . . , n} &#8594; B sm .</p><p>If (Y /S, &#953; 0 , &#951;) is a labeled G-curve, the class vector is the map of sets &#947; : {1, . . . , n} &#8594; G * such that &#947;(i) = &#947; &#951;(i) . We write &#947; = (&#947;(1), . . . , &#947;(n)). If &#947; is a class vector, we denote its inertia type by &#947; :</p><p>Let &#950; &#8467; &#8712; k be a primitive &#8467;th root of unity. The automorphism &#953; 0 (1) induces an action on H 0 (Y s , &#8486; 1 ). Let L i be the</p><p>There is an eigenspace decomposition:</p><p>Let s i = dim(L i ). Then L 0 = {0} and s 0 = 0 since Y /&#953; 0 (G) has genus 0. The signature type is (s 1 , . . . , s &#8467;-1 ). It is locally constant on S. For an integer t, let t &#8467; = t &#8467; -t &#8467; denote the fractional part of t &#8467; .</p><p>Lemma 2.1. For 1 &#8804; i &#8804; &#8467; -1,</p><p>Proof. This can be found in [19, Lem. 2.7, &#167;3.2], or deduced from earlier results [7, Lem. 4.3] (the negative sign does not appear for the action on O) or [13, Prop. 1].</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="2.3">Restrictions on the p-rank</head><p>Let &#181; p be the kernel of Frobenius on G m . The p-rank of a semi-abelian variety A over k is f A = dim F p Hom(&#181; p , A ). If A is an extension of an abelian variety A by a torus T, then</p><p>For an abelian variety A, the p-rank can also be defined as the integer f A such that the number of p-torsion</p><p>Recall that &#8467; = p is prime. Let e be the order of p in the multiplicative group (Z/&#8467;Z) &#215; .</p><p>Lemma 2.2. Suppose that Y &#8594; P 1 k is a Z/&#8467;Z-cover. Let f be the p-rank of Y. 1. Then f is divisible by e, the order of p modulo &#8467;.</p><p>Proof. The action of Z/&#8467;Z on Y induces an action of &#950; &#8467; on J = Jac(Y ) and its p-divisible group ). If m(&#955;) &gt; 0, this yields an inclusion</p><p>Then the slope 1/2 factor of J[p &#8734; ] is the p-divisible group of a supersingular elliptic curve. So Q(&#950; &#8467; ) &#8834; E where E is the endomorphism algebra of a supersingular elliptic curve. Then E is a quaternion algebra ramified exactly at &#8734;, p.</p><p>The only number fields contained in E are quadratic fields inert or ramified at p. This gives a contradiction if &#8467; &gt; 3 or if &#8467; = 3 and p &#8801; 1 mod 3.</p><p>The p-rank of Y equals the stable rank of the Cartier operator C.</p><p>where &#963; is the permutation of Z/&#8467;Z -{0} which sends i to p -1 i. The cycle structure of &#963; is determined by the splitting of p in Z[&#950; &#8467; ]. Recall that e is the order of p modulo &#8467;. There are (&#8467; -1)/e primes of Z[&#950; &#8467; ] lying over p with residual degree e. Each orbit of C on {L i } has cardinality e. Let O denote the set of orbits. The contribution to the p-rank from each of the e eigenspaces in an orbit o &#8712; O is bounded by the minimum of</p><p>Bouw used these ideas to find an upper bound on the p-rank, which depends only on p, &#8467;, and the inertia type &#947;; it is</p><p>Theorem 2.3 <ref type="bibr">(Bouw)</ref>. The integer B(&#947;) is an upper bound for the p-rank of a Z/&#8467;Zcover of P 1 with inertia type &#947; <ref type="bibr">[7, p. 300, (1)</ref>]. This upper bound B(&#947;) occurs as the p-rank of a Z/&#8467;Z-cover of P 1 with inertia type &#947; if p &#8805; &#8467;(n -3) [7, Th. 6.1], or if p = &#177;1 mod &#8467; <ref type="bibr">[7,</ref><ref type="bibr">Props. 7.4 and 7.8]</ref>, or if n = 4 <ref type="bibr">[7,</ref><ref type="bibr">Prop. 7.7]</ref>.</p><p>&#167;3. The moduli space of Z/&#8467;Z-covers and its boundary</p><p>In this section, we introduce the material needed to study p-ranks of cyclic covers from a moduli-theoretic approach. Recall that G = Z/&#8467;Z.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.1">Moduli spaces of stable Z/&#8467;Z-covers</head><p>We define moduli functors on the category of schemes over k whose S -points represent the listed objects:</p><p>1. T &#8467;,g : admissible stable G-curves (Y /S, &#953; 0 ) with Y /S of genus g. 2. T &#8467;,g : (Y /S, &#953; 0 ) as above, together with a labeling &#951; of the smooth ramification locus. 3. T &#8467;,g;t : (Y /S, &#953;, &#951;) as above, together with a mark R &#926; of degree t such that (Y /S, R &#926; ) is stably marked.</p><p>Let T &#8467;,g &#8834; T &#8467;,g be the sublocus representing smooth G-curves. Let &#947; : {1, . . . , n} &#8594; (Z/&#8467;Z) * be a class vector of length n = n(&#947;). By (1), &#947; determines the genus g = g(&#947;) = (n -2)(&#8467; -1)/2. Let T &#8467;,&#947; &#8834; T &#8467;,g be the substack for which (Y /S, &#953; 0 , &#951;) has class vector &#947;. Let T &#8467;,&#947; &#8834; T &#8467;,g be the substack for which (Y /S, &#953; 0 ) has inertia type &#947;.</p><p>If two class vectors &#947; and &#947; yield the same inertia type, so that &#947; = &#947; , then there is a permutation of {1, . . . , n} such that &#947; = &#947; &#8226; . This relabeling of the branch locus yields an isomorphism T &#8467;,&#947; T &#8467;,&#947;&#8226; . Suppose &#947; and &#947; differ by an automorphism of G, so that there exists &#964; &#8712; Aut(G) such that &#947; = &#964; &#8226; &#947;. This relabeling of the G-action yields an isomorphism T &#8467;,&#947; T &#8467;,&#964; &#8226;&#947; . Lemma 3.1. 1. T &#8467;,g and T &#8467;,g are smooth, proper Deligne-Mumford stacks over k. 2. T &#8467;,g is open and dense in T &#8467;,g .</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>3.</head><p>The forgetful functor T &#8467;,&#947; &#8594; T &#8467;,&#947; is &#233;tale and Galois. 4. T &#8467;,&#947; is an irreducible component of T &#8467;,g .</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.">The dimension of T</head></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.2">Clutching maps</head><p>We review the clutching maps &#954; g 1 ,g 2 and &#955; g 1 ,g 2 of <ref type="bibr">[15]</ref>. Each of these is the restriction of a finite, unramified morphism between moduli spaces of labeled curves. They can be described in terms of their images on S -points for an arbitrary k -scheme S. We give explicit descriptions only for sufficiently general S -points and defer to <ref type="bibr">[15]</ref> for complete definitions. A stable curve Y has compact type if its dual graph is a tree or, equivalently, if Pic 0 (Y ) is represented by an abelian scheme.</p><p>For i = 1, 2, let &#947; i denote a class vector with length n i = n i (&#947; i ) and let g i = g(&#947; i ).</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.2.1.">Clutching maps (compact type)</head><p>There is a closed immersion [15, Cor. 3.9]</p><p>This clutching map glues two curves Y 1 /S and Y 2 /S together to form a curve Y /S by identifying the last section of Y 1 and the first section of Y 2 in an ordinary double point. As seen in [3, &#167;2.3], the clutching map extends to the moduli space of labeled Z/&#8467;Z-curves as follows. Let g = g 1 + g 2 and n = n 1 + n 2 -2 and</p><p>If (Y i /S, &#953; 0,i , &#951; i ) is a labeled G-curve with class vector &#947; i , for i = 1, 2, then the clutched curve Y /S has genus g and admits a G-action &#953; 0 and a labeling &#951; with class vector &#947;. Moreover, Y /S can be deformed to a smooth G-curve if and only if the G-action is admissible, that is, if and only if &#947; 1 (n 1 ) and &#947; 2 (1) are inverses <ref type="bibr">[8,</ref><ref type="bibr">Prop. 2.2]</ref>. In this situation, we write</p><p>The signature type of (Y /S, &#953; 0 ) is the sum of those for (Y i /S, &#953; 0,i ).</p><p>, where g 2 = g -g 1 and (&#947; 1 , &#947; 2 ) ranges over the appropriate admissible pairs of class vectors.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.2.2.">Clutching maps (non-compact type)</head><p>In this case, let g = g 1 + g 2 + (&#8467; -1) and n = n 1 + n 2 and &#947; = (&#947; 1 (1), . . . , &#947; 1 (n 1 ), &#947; 2 (1), . . . , &#947; 2 (n 2 )). The other clutching maps are</p><p>To define &#955; g 1 ,g 2 , consider a Z/&#8467;Z-curve (Y i /S, &#953; 0,i ) with a mark P i , for i = 1, 2. One can glue these curves together to form a curve Y /S by identifying the orbits of P 1 and P 2 in &#8467; ordinary double points. (Specifically, identify &#953; 0,1 (g)(P 1 ) and &#953; 0,2 (g)(P 2 ) for g &#8712; G.) Then Y /S admits a G-action &#953; 0 and has inertia type &#947;.</p><p>Since Y 1 and Y 2 intersect in more than one point, the curve Y /S has non-compact type. By [6, Ex. 9.2.8], Pic 0 (Y ) is an extension</p><p>where Z is an (&#8467; -1)-dimensional torus. Thus, Y has genus g and the p-rank of Y is</p><p>There is an action of Z/&#8467;Z on Z, and each of the nontrivial eigenspaces has dimension 1; we define the signature type of Z to be (1, . . . , 1). The signature type of (Y /S, &#953;) is the sum of those for (Y i /S, &#953; 0,i ) and Z.</p><p>For 0</p><p>] is the set of moduli points of stable Z/&#8467;Z-curves of genus g which are not of compact type.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.3">Components and dimension of the boundary</head><p>The boundary of T &#8467;,g is &#948;T &#8467;,g = T &#8467;,g -T &#8467;,g . If g &#8805; 2, then &#948;T &#8467;,g is the union of</p><p>, some of which may be empty. Note that &#8710; i and &#8710; g-i (resp. &#926; i and &#926; g-i-(&#8467;-1) ) are the same substack of T &#8467;,g .</p><p>If S is a stack with a map S &#8594; T &#8467;,g , let</p><p>Proof. Let W be an irreducible component of &#948;T &#8467;,g . There is an inertia type &#947; such that W is either a component of (i</p><p>. By Lemma 3.1 <ref type="bibr">(5)</ref>, it suffices to show that dim(W ) = n -4.</p><p>Case (i): In this case, a generic point of W is the moduli point of a singular curve Y with two irreducible components Y 1 and Y 2 intersecting in one ordinary double point y. Let &#947; i be the inertia type of the restriction of the Z/&#8467;Z-action to Y i , and let</p><p>Case (ii): In this case, a generic point of W is the moduli point of a singular curve Y with two irreducible components Y 1 and Y 2 , of genera i and g -i -(&#8467; -1) intersecting at one unramified Z/&#8467;Z-orbit. Let &#947; i be the inertia type of the restriction of the Z/&#8467;Z-action to Y i , and let</p><p>The next result is used to find an upper bound on the dimension of the p-rank strata. Proposition 3.3. If S &#8834; T &#8467;,g has the property that S intersects &#8710; i , then</p><p>Proof. A smooth proper stack has the same intersection-theoretic properties as a smooth proper scheme <ref type="bibr">[23, p. 614</ref>]. In particular, if two closed substacks of T g intersect, then the codimension of their intersection is at most the sum of their codimensions. Now, &#8710; i [T &#8467;,g ] is a closed substack of T &#8467;,g . It suffices to consider the case that S is closed. Thus,</p><p>The result follows from Lemma 3.2 since codim(&#8710; i , T &#8467;,g ) = 1.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.4">The p-rank stratification</head><p>If A is a semi-abelian scheme over a Deligne-Mumford stack S, then there is a stratification S = &#8746;S f by locally closed reduced substacks such that s &#8712; S f (k) if and only if f (A s ) = f [14, Th. 2.3.1] (see also [4, Lem. 2.1]). For example, T f &#8467;,g is the locally closed reduced substack of T &#8467;,g whose points represent smooth Z/&#8467;Z-curves of genus g with prank f.</p><p>We use the following notation for the p-rank f stratum of the boundary:</p><p>. These strata are easy to describe using the clutching maps. First, if 1</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="3.5">Shimura varieties</head><p>We briefly review some notation about Shimura varieties that we need in &#167; &#167;5.3 and 6.2. We refer to <ref type="bibr">[17, &#167;3.3]</ref> for a longer explanation. Notation 3.4. Let &#8467; be an odd prime. Consider an inertia type &#947; for &#8467;. It determines the number of branch points n = n(&#947;) and the genus g = g(&#947;) as in (1) for a Z/&#8467;Z-cover Y &#8594; P 1 with inertia type &#947;. Furthermore, it determines the signature type of the cover as in Lemma 2.1.</p><p>Recall that T &#8467;,&#947; is the moduli space of Z/&#8467;Z-covers Y &#8594; P 1 with inertia type &#947;. By Lemma 3.1, T &#8467;,&#947; is irreducible and has dimension n(&#947;) -3. Notation 3.5. Let A g be the moduli space of principally polarized abelian varieties of dimension g. Consider the image of T &#8467;,&#947; in A g . Let Z &#947; = Z(&#8467;, n, &#947;) be the closure of this image; its points represent Jacobians of curves (smooth or of compact type) that admit a Z/&#8467;Z-cover of P 1 with inertia type &#947;.</p><p>Attached to the data of &#8467; and the signature type, there is a PEL-type Shimura variety Sh. Let &#931; &#947; = &#931;(&#8467;, n, &#947;) be the irreducible component of Sh that contains Z &#947; .</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>&#167;4. Intersection of the p-rank 0 stratum with the boundary</head><p>In this section, we study the geometry of the p-rank stratification on the moduli space of cyclic degree &#8467; covers of the projective line.</p><p>Recall that p is a prime such that p = &#8467; and e is the order of p modulo &#8467;. The formula for the upper bound B(&#947;) for the p-rank of a cover with inertia type &#947; is in <ref type="bibr">(2)</ref>. Let f be a multiple of e such that 0 &#8804; f &lt; B(&#947;). Define = 1 if p &#8801; 1 mod &#8467; and = 0 otherwise.</p><p>We first give a lower bound on the dimension of the p-rank strata. </p><p>Proof. The p-ranks which occur on T &#8467;,&#947; are multiples of e by Lemma 2.2 and are at most B(&#947;) by Theorem 2.3. Furthermore, if p &#8801; 1 mod &#8467;, then e = 1 and f = g -1 = B(&#947;) -1 by Lemma 2.2. So the number of integers f such that f &lt; f &#8804; B(&#947;) which can occur as the p-ranks for points of T &#8467;,&#947; is at most (B(&#947;) -f )/e + . The statement is then an immediate application of the purity result of Oort <ref type="bibr">[20,</ref><ref type="bibr">Lem. 1.6]</ref> which states that if the p-rank changes, then it does so on a subspace of codimension 1.</p><p>Remark 4.2. For &#8467; &#8805; 5, the lower bound on the right-hand side of ( <ref type="formula">5</ref>) is positive only when f is large relative to g. For example, if &#8467; = 5 and p &#8801; 1 mod 5, then it is -g/2 + f . In the next result, assuming that the p-rank 0 stratum T 0 &#8467;,&#947; is non-empty, we show that it intersects the boundary deeply (in the sense that the intersection contains points corresponding to reducible curves with many components). Theorem 4.3. Suppose S is an irreducible component of the p-rank 0 stratum T 0 &#8467;,&#947; of T &#8467;,&#947; . Let &#963; = dim(S). Then there exists &#951; &#8712; S such that the curve Y &#951; of compact type represented by &#951; is reducible, with at least &#963; + 1 components, such that the Z/&#8467;Z-action stabilizes and acts nontrivially on each component.</p><p>Before proving this theorem, we explain its significance. In contrast, when &#8467; is odd, then usually &#963; &lt; g -1. Thus, Theorem 4.3 does not imply that T 0 &#8467;,&#947; contains a point representing a reducible curve with g components. This makes it harder to study the case when &#8467; is odd. 4. It is not possible to prove Theorem 4.3 using results on the boundary of the moduli space of n-marked curves of genus 0. The reason is that the relationship between the p-rank and the location of the branch points is extremely complicated. As an example of this, see the case that &#8467; = 3 and g = 2 studied in Lemma 7.1. In other words, it is not clear how to maintain the p-rank 0 condition when deforming the curve by moving the branch points.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>Proof. (Proof of Theorem 4.3).</head><p>The proof is by induction on the number of branch points n = n(&#947;). This is equivalent to induction on the genus g = g(&#947;), because g = (n -2)(&#8467; -1)/2. For the base case, when n = 3 and g = (&#8467; -1)/2, the statement is vacuous since T &#8467;,&#947; has dimension 0.</p><p>Suppose that the statement is true for all inertia types &#947; for which the genus g is less than g. Let &#947; be an inertia type for which the genus is g, and let S be an irreducible component of T 0 &#8467;,&#947; . When &#963; = 0, the statement is vacuous. Suppose &#963; &gt; 0. Since T &#8467;,&#947; is affine, S intersects a boundary component of T &#8467;,&#947; . The points of S represent curves whose p-rank is 0, and hence (4) implies that S does not intersect &#8710; 0 . Thus, S intersects &#8710; j for some 1 &#8804; j &#8804; g -1. A point of &#8710; j [S] represents a curve having at least two components (which completes the proof when &#963; = 1).</p><p>By Proposition 3.</p><p>is in the image of a clutching morphism. Specifically, there is an admissible pair of inertia types &#947; 1 , &#947; 2 , and points &#958; i &#8712; T&#8467;,&#947; i , for i = 1, 2, such that &#951; 0 = &#954; j,g-j (&#958; 1 , &#958; 2 ). Since S is an irreducible component of</p><p>By the inductive hypothesis, for i = 1, 2, there exists &#951; i &#8712; &#915; i such that the curve Y &#951; i of compact type represented by &#951; i has at least &#963; i +1 components. Then &#954; j,g-j (&#951; 1 , &#951; 2 ) &#8712; &#8710; j [S] has at least (&#963; 1 +1)+(&#963; 2 +1) &#8805; &#963; +1 components.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>&#167;5. Trielliptic covers</head><p>In this section, we specialize to the case &#8467; = 3. Suppose p = 3 is prime. We study the p-ranks of trielliptic curves, which are Z/3Z-covers of P 1 . Suppose g &#8805; 2 and (r, s) is a signature type for g.</p><p>In Proposition 5.9, for all primes p &#8805; 5, we prove that there exists a trielliptic curve Y defined over F p of genus g and signature (r, s) whose p-rank is smaller than the upper bound B(r, s).</p><p>In Theorem 5.11, when p &#8801; 2 mod 3 is odd, we prove that every integer f satisfying the necessary conditions from Lemma 2.2 occurs as the p-rank of a trielliptic curve Y defined over F p of genus g and signature (r, s); in addition, we prove that there is an irreducible component of T f g,(r,s) whose dimension equals the lower bound from Proposition 4.1.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.1">Notation for trielliptic covers</head><p>Suppose (Y /S, &#953; 0 ) is a smooth trielliptic curve. The Z/3Z-cover &#968; : Y &#8594; P 1 has an equation of the form:</p><p>Without loss of generality, we assume that &#968; is not branched at &#8734;.</p><p>The number of branch points of &#968; is n = d 1 + d 2 and the genus of Y is g = d 1 + d 2 -2. The inertia type of &#968; is &#947; = (1, . . . , 1 d 1 , 2, . . . , 2 d 2 ). Lemma 5.1 [3, Lem. 2.7]. The set of inertia types &#947; for a trielliptic curve (Y /S, &#953; 0 ) of genus g is in bijection with</p><p>3 &#969;. The signature type of (Y /S, &#953; 0 ) is (r, s) where r = dim(L 1 ) and s = dim(L 2 ). If (Y /S, &#953; 0 ) is a trielliptic curve, then so is (Y /S, &#953; 0 ) where &#953; 0 (1) = &#953; 0 (2). Replacing &#953; 0 with &#953; 0 exchanges the values of d 1 and d 2 and the values of r and s. Definition 5.2. A trielliptic signature for g &#8712; N is a pair (r, s) of integers with r +s = g, and 0 &#8804; max{r, s} &#8804; 2min{r, s} + 1.</p><p>The next result follows from Lemma 2.1 Lemma 5.3. There is a bijection between trielliptic signatures (r, s) for g and inertia types of Z/3Z-Galois covers of P 1 of genus g given by the formulae</p><p>In other words, r = (2d 1 + d 2 -3)/3 and s = (d 1 + 2d 2 -3)/3. Example 5.4 (Signature (1, 0), inertia type &#947; = (1, 1, 1)). There is a unique smooth elliptic curve which is trielliptic. It has p-rank 0 when p &#8801; 2 mod 3 and p-rank 1 when p &#8801; 1 mod 3.</p><p>Proof. By <ref type="bibr">[22,</ref><ref type="bibr">Th. 10</ref>.1], an elliptic curve with automorphism of order 3 has j -invariant 0. The result follows from [22, Exer. V.5.7 and Exam. V.4.4].</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.2">Components of the moduli space and maximal p-rank</head><p>Let (r, s) be a trielliptic signature for g. Let &#947; be the inertia type given by &#947;(i) = d i where d i are as in Lemma 5.3. Let f be an integer 0 &#8804; f &#8804; g satisfying the conditions of Lemma 2.2, namely, f is even if p &#8801; 2 mod 3 and f = g -1 if p &#8801; 1 mod 3.</p><p>Consider the moduli space T (r,s) = T 3,&#947; of smooth trielliptic curves with signature (r, s) and inertia type &#947;. For f as above, let T f (r,s) denote the p-rank f stratum of T (r,s) . Similarly, define T f (r,s) by replacing the word smooth by stable. The next result is a special case of Proposition 4.1.</p><p>Proposition 5.5. Suppose S is an irreducible component of T f (r,s) . If p &#8801; 2 mod 3, then dim(S) &#8805; max{r, s} -1 + f /2. If p &#8801; 1 mod 3 and f &lt; g, then dim(S) &#8805; f . We first consider the case of maximal p-rank. Define B(r, s) = g if p &#8801; 1 mod 3 and B(r, s) = 2 min{r, s} if p &#8801; 2 mod 3. By Theorem 2.3, the p-rank of a trielliptic curve of signature (r, s) satisfies f &#8804; B(r, s). Proposition 5.6 <ref type="bibr">[Bouw]</ref>. If p = 3, then there exists a smooth trielliptic curve with signature (r, s) and p-rank f max := B(r, s). The p-rank f max strata T f max (r,s) is open and dense in T (r,s) .</p><p>Proof. The first statement is a special case of [7, Props. 7.4 and 7.8]. The second statement follows since T (r,s) is irreducible and the p-rank is lower semi-continuous.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.3">Base cases</head><p>Moonen proved there are exactly 20 families of cyclic covers of P 1 that are special, meaning that the image of the family under the Torelli morphism is open and dense in the associated unitary Shimura variety; these are listed as M [1]-M <ref type="bibr">[20]</ref> in [19, Table 1]. In [17,  &#167; &#167;4-6], the authors computed the Newton polygons occurring on these families. In <ref type="bibr">[17,</ref><ref type="bibr">Th. 5.11</ref>] and <ref type="bibr">[16,</ref><ref type="bibr">Th. 7</ref>.1], they proved that each of these Newton polygons occurs for the Jacobian of a smooth curve in the family, except possibly the supersingular ones when p is small.</p><p>For trielliptic covers, there are three families that are special: M [3], M <ref type="bibr">[6]</ref>, and M <ref type="bibr">[10]</ref>. Since the p-rank is an invariant of the Newton polygon, we can find the dimension of the p-rank strata of these families. When the Newton polygon is supersingular (which happens only when f = 0), we can remove the requirement that p &gt;&gt; 0 in all but one case.</p><p>The results below for the signature (r, s) are also true for the signature (s, r). If p &#8801; 1 mod 3 and f = 0, 1, 2, then T f (1,3) is non-empty of dimension f (if p &gt;&gt; 0 when f = 0). If p &#8801; 2 mod 3 and f = 0, then T 0 (1,3) is non-empty of dimension 2.</p><p>Proof. The Newton polygons for the curves in the family are listed on <ref type="bibr">[17, p. 19</ref>].</p><p>1. When f = 0, then the Newton polygon of a curve in the family is supersingular. If p &#8801; 1 mod 3, the result follows from <ref type="bibr">[17,</ref><ref type="bibr">Th. 5.11]</ref>. The main idea is that, because of Example 5.4, a supersingular curve in the family must be smooth. When p &#8801; 2 mod 3 is odd, the result follows from Lemma 7.1 (or [16, Th. 7.1] when p &gt;&gt; 0). 2. When p &#8801; 1 mod 3, the result follows from <ref type="bibr">[17,</ref><ref type="bibr">Th. 5.11]</ref>; note that the Newton polygon has slopes 1/3 and 2/3 when f = 0. When p &#8801; 2 mod 3, the result follows from <ref type="bibr">[16,</ref><ref type="bibr">Th. 7</ref>.1] when p &gt;&gt; 0. Here is an argument that removes the hypothesis p &gt;&gt; 0. Let S be an irreducible component of the p-rank 0 locus T 0 (2,1) . Then dim(S) = 1 because T (2,1) has dimension 2 and its generic geometric point represents a curve with p-rank 2. The intersection of S with the boundary is contained in</p><p>), but that only has dimension 0, so the generic geometric point of S represents a smooth curve. 3. When p &#8801; 1 mod 3, the result follows from <ref type="bibr">[16,</ref><ref type="bibr">Th. 7</ref>.1]; we do not know how to remove the hypothesis p &gt;&gt; 0 when f = 0. When p &#8801; 2 mod 3, then T 0 (1,3) is non-empty of dimension 2 by <ref type="bibr">[17,</ref><ref type="bibr">Th. 5.11</ref>]. For the family M [10], we consider the unitary Shimura variety Sh attached to the data of &#8467; = 3 and the signature type <ref type="bibr">(3,</ref><ref type="bibr">1)</ref>. As in &#167;3.5, let &#931; be the irreducible component of Sh which contains the Torelli locus.</p><p>Proposition 5.8. Suppose p &#8801; 2 mod 3. For the family M <ref type="bibr">[10]</ref>, the p-rank 0 stratum &#931; 0 of &#931; is irreducible and thus T 0 (1,3) is irreducible. Proof. For each generic geometric point of &#931; 0 , we consider the Newton polygon &#957; of the abelian variety represented by this point. Applying the Kottwitz method (see [17, &#167;4.3 and table on p. 19]) shows that &#957; has slopes 1/4 and 3/4 when p &#8801; 2 mod 3; in particular, it is not supersingular. The hypotheses of <ref type="bibr">[1,</ref><ref type="bibr">Th. 1.1]</ref> are satisfied; the conclusion of that result is that the stratum of &#931; with Newton polygon &#957; is irreducible. Since this stratum is open and dense in &#931; 0 , this implies that &#931; 0 is irreducible.</p><p>Since the family M <ref type="bibr">[10]</ref> is special, the image of T <ref type="bibr">(3,</ref><ref type="bibr">1)</ref> is open and dense in &#931;. It follows that T 0 (3,1) is open and dense in &#931; 0 . Thus, T 0 (3,1) is irreducible as well.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.4">Trielliptic curves whose p-rank is not maximal</head><p>The next result extends Proposition 5.6 by showing, for each prime p &#8805; 5, that there exist trielliptic curves of each signature type (r, s) whose p-rank is not the maximum B(r, s). Recall that B(r, s) = 2min{r, s} when p &#8801; 2 mod 3 and B(r, s) = r + s when p &#8801; 1 mod 3. Proposition 5.9. Let p &#8805; 5 and g &#8805; 2. Let (r, s) be a trielliptic signature for g. Then T B(r,s)-2 (r,s) is non-empty, and each of its irreducible components has dimension g -2 (codimension 1 in T (r,s) ). Thus, there exists a smooth trielliptic curve with signature (r, s) and p-rank f = B(r, s) -2.</p><p>Proof. Recall that dim(T (r,s) ) = g -1 and the generic geometric point of T (r,s) represents a trielliptic curve with p-rank B(r, s) by Proposition 5.6. If T B(r,s)-2 (r,s) is non-empty, then, by definition, each of its generic geometric points represents a smooth trielliptic curve with signature (r, s) and p-rank f = B(r, s) -2. Furthermore, if S is one of the irreducible components of T B(r,s)-2 (r,s)</p><p>, then dim(S) &#8804; g -2 and Proposition 5.5 implies that dim(S) &#8805; g -2, so dim(S) = g -2.</p><p>It thus suffices to prove that T B(r,s)-2 (r,s)</p><p>is non-empty. Without loss of generality, suppose r &#8804; s. The proof is by induction on r.</p><p>If r = 1, then 1 &#8804; s &#8804; 3. If r = 1 and s = 1, then B(1, 1) -2 = 0 and the result follows from Lemma 5.7(1) (deferred to Lemma 7.1(1) when p &#8801; 2 mod 3). If r = 1 and s = 2, then B(1, 2) -2 = 1 when p &#8801; 1 mod 3 and B(1, 2) -2 = 0 when p &#8801; 2 mod 3 and the result follows from Lemma 5.7 <ref type="bibr">(2)</ref>. If r = 1 and s = 3, then B(1, 3) -2 = 2 when p &#8801; 1 mod 3 and B(1, 3) -2 = 0 when p &#8801; 2 mod 3, and the result follows from Lemma 5.7 <ref type="bibr">(3)</ref>. Now, suppose 2 &#8804; r &#8804; s.</p><p>Case 1: Suppose s &#8804; 2r. Then (r -1, s -1) is a valid trielliptic signature. Note that B(r -1, s -1) = B(r, s) -2. Let S 1 be an irreducible component of T 0</p><p>(1,1) , which is nonempty when p &#8805; 5 by Lemma 5.7 <ref type="bibr">(1)</ref>. Let S 2 be an irreducible component of T B(r-1,s-1) (r-1,s-1) , which is non-empty by Proposition 5.6. Consider an irreducible component S 1 of T 0</p><p>(1,1) lying above S 1 and an irreducible component</p><p>lying above S 2 . When (r, s) = (1, 1), then d 1 = d 2 = 2 are both positive. Thus, without loss of generality, we can choose S 1 (the labeling of the ramification points) so that the clutching situation below is admissible:</p><p>].</p><p>Let W be an irreducible component of T B(r,s)-2 (r,s) which contains K. By the same reasoning as the first paragraph of the proof, dim(W ) = g -2. On the other hand, since dim( S 1 ) = 0 and dim( T (r-1,s-1) ) = g -3, it follows that dim(K) = dim( S 1 ) + dim( T(r-1,s-1) ) = g -3.</p><p>Thus, the generic point of W is not contained in K.</p><p>By construction, the generic point of S 1 represents a smooth curve. The generic point of T B(r-1,s-1) (r-1,s-1) represents a smooth curve by Proposition 5.6 and Lemma 3.2. So the generic point of W is not contained in any other boundary component. Thus, the generic point of W represents a smooth curve and T B(r,s)-2 (r,s) is non-empty, with irreducible components of dimension g -2.</p><p>Case 2: Suppose s = 2r + 1. Then (r -1, s -2) is a valid trielliptic signature. Note that B(r -1, s -2) = 2(r -1) when p &#8801; 2 mod 3 and B(r -1, s -2) = g -3 when p &#8801; 1 mod 3. Let f = 0 when p &#8801; 2 mod 3 and f = 1 when p &#8801; 1 mod 3. Then f +B(r -1, s-2) = B(r, s)-2.</p><p>Let S 1 be an irreducible component of T f (1,2) , which is non-empty by Lemma 5.7(2). Let S 2 be an irreducible component of T B(r-1,s-2) (r-1,s-2) , which is non-empty by Proposition 5.6. When (r, s) = (1, 2), then d 1 = 1 and d 2 = 4, which are both positive. We repeat the argument above, making an admissible clutching of the following form:</p><p>.</p><p>The rest of the proof is the same. Remark 5.10. When p = 2, then T 0 (1,1) is empty, as shown in Lemma 7.1 <ref type="bibr">(2)</ref>. When p = 2, it is still true that T 0 (1,1) is non-empty (of dimension 0); the same proof as for Proposition 5.9 shows that T B(r,s)-2 (r,s) is non-empty and each of its irreducible components has dimension g -2 (codimension 1 in T (r,s) ), but it is not clear whether any of its points represents a smooth curve.</p><p>The case when p = 3 is described in Proposition 7.4.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="5.5">Existence of trielliptic curves with given p-rank</head><p>In this section, suppose p &#8801; 2 mod 3. In this case, the necessary conditions on the prank are that f is even and 0 &#8804; f &#8804; 2min(r, s). For every signature type and for all odd p &#8801; 2 mod 3, we prove that every p-rank f satisfying the necessary conditions occurs for a smooth trielliptic curve of that signature in characteristic p. If S is an irreducible component of T f (r,s) , recall from Proposition 5.5 that dim(S) &#8805; max{r, s} -1 + f /2. Theorem 5.11. Let p &#8801; 2 mod 3 be odd, and let g &#8805; 2. Let (r, s) be a trielliptic signature for g. Suppose 0 &#8804; f &#8804; 2min{r, s} is even. Then there exists a smooth trielliptic curve of genus g defined over F p with signature type (r, s) and p-rank f. More generally, T f (r,s) is nonempty and contains an irreducible component S = S f (r,s) with dim(S) = max{r, s} -1 + f /2.</p><p>Proof. The first statement about the existence of the trielliptic curve with signature type (r, s) and p-rank f is equivalent to the statement that T f (r,s) is non-empty. To prove this, without loss of generality, suppose r &#8804; s. The proof is by induction on r, with the result being true for r = 1 by Proposition 5.6 when f = 2 and Lemma 5.7 when f = 0. Suppose the result is true for all trielliptic signatures (r 1 , s 1 ) with 1 &#8804; r 1 &lt; r.</p><p>Let (r 2 , s 2 ) be either (i) (1, 2) or (ii) (1, 1), with choice (i) mandated if s = 2r + 1 and choice (ii) mandated if s = r. Let g 2 = r 2 +s 2 . Let r 1 = r -r 2 and s 1 = s-s 2 , and g 1 = r 1 +s 1 . Note that (r 1 , s 1 ) is a trielliptic signature for g 1 and r 1 &#8804; s 1 .</p><p>By the hypothesis, 0 &#8804; f &#8804; 2r is even. Let f 2 be either (a) 2 or (b) 0, with choice (a) mandated if f = 2r and choice (b</p><p>It follows that T f i (r i ,s i ) is non-empty and contains an irreducible component S i with dim(S i ) = s i -1 + f i /2 (by the inductive hypothesis when i = 1, Propositions 5.6 and 5.9 when i = 2). One can add a labeling of the smooth ramification points by choosing an irreducible component Si of T(r i ,s i ) above S i .</p><p>Finally, the generic point of W is not contained in K. Since the generic points of S 1 and S 2 represent smooth curves (this requires the hypothesis p = 2 for case (ii)), the generic point of W is not contained in any other boundary component. Thus, the generic point of W represents a smooth curve. It follows that S = W &#8745; T f (r,s) is open and dense in W and thus is non-empty with dimension s -1 + f /2. Remark 5.12. When p &#8801; 1 mod 3, we were not able to prove an analogue of Theorem 5.11. Then main reason is that if f &lt; g and if S is an irreducible component of T f (r,s) , then Proposition 5.5 states that dim(S) &#8805; f . When f = 0, the expected dimension is 0, which makes it difficult to work with the p-rank 0 stratum inductively.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head>&#167;6.</head><p>Cases where all p-rank 0 strata have the same dimension Suppose p &#8801; 2 mod 3 is odd. Let g &#8805; 2. Let (r, s) be a trielliptic signature for g. Let f be an even integer such that 0 &#8804; f &#8804; 2min{r, s}. If S is an irreducible component of T f (r,s) , then dim(S) &#8805; max{r, s} -1 + f /2 by Proposition 5.5.</p><p>We proved in Theorem 5.11 that T f (r,s) is non-empty and contains an irreducible component with dim(S) = max{r, s} -1 + f /2. Motivated by a result in the hyperelliptic case <ref type="bibr">[11,</ref><ref type="bibr">Prop. 2]</ref>, we tried to prove that every component of T f (r,s) has the same dimension. This is true when min{r, s} = 1 by Lemma 5.7. In this section, we prove it is also true when min{r, s} = 2 (see <ref type="bibr">Corollary 6.4)</ref>.</p><p>Here are some of the reasons the trielliptic case is more difficult than the hyperelliptic case. First, it is possible that there are components of T f r,s that are fully contained in the boundary. This does not happen in the hyperelliptic case by <ref type="bibr">[5,</ref><ref type="bibr">Lem. 3.2]</ref>. We describe this in &#167;7.2.</p><p>Second, in the hyperelliptic case, every irreducible component of the p-rank 0 stratum H 0 g contains the moduli point of a tree of g (supersingular) elliptic curves <ref type="bibr">[5,</ref><ref type="bibr">Th. 3.11(c)</ref>]. The analogous result in the trielliptic case is weaker. By Theorem 4.3, every irreducible component of T 0 (r,s) contains the moduli point of a tree of max{r, s} trielliptic curves, but max{r, s} is strictly less than g.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="6.1">Balanced degenerations</head><p>In this section, we introduce balanced degenerations which are helpful for finding an upper bound for the dimension of irreducible components. The reason for the balanced condition is that B(r, s) is not additive in general. When p &#8801; 2 mod 3 and r &#8804; s, then B(r, s) = B(r 1 , s 1 ) + B(r 2 , s 2 ) if and only if r 1 &#8804; s 1 and r 2 &#8804; s 2 . Definition 6.1. Let S be an irreducible component of T f (r,s) with r &#8804; s. We say S degenerates to &#8710;((r 1 , s 1 )</p><p>). We say the degeneration is balanced if r 1 &#8804; s 1 and r 2 &#8804; s 2 .</p><p>In Definition 6.1, we implicitly require that (r 1 , s 1 ) and (r 2 , s 2 ) are trielliptic signatures, that r 1 + r 2 = r and s 1 + s 2 = s, that f i are even with 0 &#8804; f i &#8804; 2r i , and that f 1 + f 2 &#8804; f . Proposition 6.2. Suppose S has a balanced degeneration to &#8710;((r 1 , s 1 )</p><p>Then dim(S) = s -1 + f /2 and S contains &#954;(S 1 &#215; S 2 ), where S i denotes a component of</p><p>Proof. By Theorem 5.5, dim(S) &#8805; s -1 + f /2. By Proposition 3.3,</p><p>Since the degeneration is balanced, r i &#8804; s i . By hypothesis,</p><p>Thus, dim(S) = s -1 + f /2. Furthermore, S contains &#954;(S 1 &#215; S 2 ) in order for equality to hold in the dimension count.</p><p>There is an analogous result for the other boundary components, which we do not need in this paper. In this case, we say S degenerates to &#926;((r 1 , s 1 )</p><p>(r 2 ,s 2 );1 ). In this case, we allow (r 1 , s 1 ) = (0, 0) to be a valid trielliptic signature, and require that r 1 + r 2 = r -1 and s 1 + s 2 = s -1, and</p><p>Proposition 6.3. Suppose S has a balanced degeneration to &#926;((r 1 , s 1 ) f 1 , (r 2 , s 2 ) f 2 ). For i = 1, 2, suppose ( <ref type="formula">7</ref>) is true. Then dim(S) = s -1 + f /2 and S contains &#955;(S 1 &#215; S 2 ), where S i denotes a component of</p><p>Proof. The proof is almost the same as for Proposition 6.2. For a &#926;-degeneration, recall that s 1 + s 2 = s -1, r 1 + r 2 = r -1, and f 1 + f 2 &#8804; f -2. Marking an orbit increases the dimension by 1, so dim(T</p><p>6.2 A partial generalization of Proposition 5.9 When f = B(r, s) -2, then the p-rank f stratum has codimension 1 in T (r,s) , by Proposition 5.9. When p &#8801; 2 mod 3 is odd, by Theorem 5.11, T f (r,s) is non-empty for each 0 &#8804; f &#8804; 2min{r, s} with f even.</p><p>When p &#8801; 2 mod 3 is odd, we would like to generalize Proposition 5.9 by showing that every component of the p-rank f = B(r, s) -4 stratum has codimension 2 in T (r,s) . One reason this is hard to show is because it is not known whether the p-rank strata are nested in each other; specifically, it is not known whether every component of the f = B(r, s) -4 stratum is contained in the closure of the f = B(r, s) -2 stratum.</p><p>In the next result, we are able to extend Proposition 5.9 in this desired way but only under the strong restriction that min{r, s} = 2. Corollary 6.4. Let p &#8801; 2 mod 3 be odd. Let (r, s) be a trielliptic signature with min{r, s} = 2. Let f = 0. If S is an irreducible component of T 0 (r,s) , then dim(S) = max{r, s} -1.</p><p>In the rest of the section, we prove Corollary 6.4. By symmetry, it suffices to suppose r = 2; then s = 2, 3, 4, 5, and we handle these cases separately. Corollary 6.4 is an application of Theorem 4.3, which we restate in the trielliptic context: suppose S is an irreducible component of the p-rank 0 stratum T 0 (r,s) of T (r,s) ; let &#963; = dim(S); then there exists &#951; &#8712; S such that the curve Y &#951; of compact type represented by &#951; &#215; I I I I I I I I I I By Proposition 3.3, dim(S) &#8804; 3. If dim(S) = 2, the proof is complete. If dim(S) = 3, then there is a component S 1 of T 0 (1,0) and a component S 2 of T 0 (1,3) such that S contains &#954;(S 1 &#215; S 2 ).</p><p>Consider the unitary Shimura variety Sh attached to the data of &#8467; = 3 and the signature type (1, 3); let &#931; be the irreducible component of Sh which contains the Torelli locus; and let &#931; 0 denote the p-rank 0 stratum of &#931;. By Proposition 5.8, &#931; 0 is irreducible.</p><p>Consider a (labeled) tree &#951; of four elliptic curves (with dual graph in Figure <ref type="figure">3</ref>); this is a singular trielliptic curve with signature type (1, 3) and p-rank 0. Its Jacobian is represented by a point of &#931; 0 , and thus by a point in the closure of S 2 . This implies that the point &#954;(S 1 &#215; &#951; ) is in &#8710; 2 [S], which is a contradiction. Proof. By Theorem 5.5, dim(S) &#8805; 3. Since T (2,4) is affine, S intersects either &#8710; 1 or &#8710; 2 or &#8710; 3 . Then S has a balanced degeneration to either &#8710;((0, 1) 0 , (2, 3) 0 ) or &#8710;((1, 1) 0 , (1, 3) 0 ) or &#8710;((1, 2) 0 , (1, 2) 0 ). The result follows from Proposition 6.2, with the hypothesis in <ref type="bibr">(7)</ref> verified by Lemmas 5.7 and 6.5. In the dual graph of Y, we replace the vertex representing the curve of genus 2 by two vertices connected by a marked edge. One possibility for the dual graph is seen in Figure <ref type="figure">4</ref>.</p><p>Regardless of the location of the marked edge, &#951; is in &#954;( T 0 (1,2) &#215; T 0 (1,3) ). Thus, S has a balanced degeneration to &#8710;((1, 2) 0 , (1, 3) 0 ). By Proposition 6.2(1), dim(S) &#8804; 4, which gives a contradiction. Hence, dim(S) = 4.</p><p>We restrict to the case (r, s) = (1, 1) and g = 2. Then H 0 (Y, &#8486; 1 ) = L 1 &#8853; L 2 where</p><p>We suppose that p &#8801; 2 mod 3; then the Cartier operator C permutes L 1 and L 2 .</p><p>Let e 1 = (2p -1)/3 and e 2 = (p -2)/3. Note that e 1 + e 2 = p -1. Let</p><p>In this case, for i = 1, 2, there is only one monomial x e in h i (x) such that e &#8801; -1 mod p; let A i be the coefficient of x p-1 in h i (x). By a special case of <ref type="bibr">[9,</ref><ref type="bibr">Th. 3.4]</ref>,</p><p>) Lemma 7.1. 1. If p &#8801; 2 mod 3 is odd, then T 0 (1,1) is non-empty: there exists a smooth trielliptic curve Y over F p with genus 2 and p-rank 0. 2. If p = 2, then T 0 (1,1) is empty: there does not exist a smooth trielliptic curve Y over F 2 with genus 2 and 2-rank 0.</p><p>Proof.</p><p>By (8), C(&#969; 1,1 ) = A 1 &#969; 2,1 where A 1 is the coefficient of x p-1 in h 1 (x). A pair (i, j) contributes to this coefficient exactly when 2i + 2j = p -1, or j = (p -1)/2 -i. Thus,</p><p>p+1 6 +i e 1 p-1 2 -i e 2 i .</p><p>The sum has an even number of terms. One can check that the i th and (e 2 -i)th terms cancel, because ((p -1)/2 -i) + ((p -1)/2 -(e 2 -i)) = e 1 and because i and e 2 -i have opposite parities. Thus, A 1 = 0. The same argument, with the roles of e 1 and e 2 switched, shows that A 2 = 0. Thus, C is the zero operator (implying that Y is superspecial) and so Y has p-rank 0. 2. Let p = 2. After an automorphism of P 1 , one can suppose that p 1 (x) = x 2 + x + 1 and p 2 (x) = (x -1)(x -a) for some a &#8712; F 2 . Then h 1 (x) = p 1 (x) and h 2 (x) = p 2 (x), so A 1 = 1 and A 2 = -(a + 1). The determinant of the matrix of C is a + 1. If Y has 2-rank 0, then this determinant is zero, so a &#8801; 1 mod 2. Then p 2 (x) is not square-free, so Y is singular.</p><p>Elkin provides similar formulas for any prime degree &#8467; and inertia type &#947;; unfortunately, this does not provide a viable way to study the p-rank strata when g &gt; 2 and p is large for any &#8467;, because the equations are algebraically complicated.</p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="7.2">Possibility of components fully contained in the boundary</head><p>Here is an important fact about the p-rank stratification of the hyperelliptic locus. When p is odd, the generic geometric point of each irreducible component of H f g represents a smooth hyperelliptic curve, by <ref type="bibr">[5,</ref><ref type="bibr">Lem. 3.1]</ref>.</p><p>The analogue of this fact is not true in general for the trielliptic locus. For example, when p = 2, then every point of T 0 (1,1) represents a singular trielliptic curve by Lemma 7.1(2). This is the key reason for the restriction that p is odd in Proposition 5.9 and Theorem 5.11.</p><p>We give some other examples where this type of problem may occur. </p></div>
<div xmlns="http://www.tei-c.org/ns/1.0"><head n="7.3">The wild case p = 3</head><p>We include the case of trielliptic covers when p = 3. Proposition 7.4. Suppose k = F 3 . Then there exists a Z/3Z-cover of P 1 k having genus g and 3-rank 0 if and only if g &#8801; 2 mod 3. For g &#8805; 2 and 1 &#8804; e &#8804; g/2, there exists a Z/3Z-cover of P 1 k having genus g and 3-rank 2e. Proof. Suppose &#966; : Y &#8594; P 1 k is a Z/3Z-cover. Then &#966; is given by an Artin-Schreier equation of the form y 3 -y = f (x) for some f (x) &#8712; k(x). Suppose div &#8734; (f (x)) = e j=0 d j P j is the pole divisor of f (x). By Artin-Schreier theory, one can suppose that 3 d j for each j. Let e j = d j + 1.</p><p>The Riemann-Hurwitz formula and the Deuring-Shafarevich formula imply that the genus of Y is g = -2 + Thus, when p = 3, there exists a Z/3Z-cover of P 1 k having genus g and 3-rank 0 if and only if g &#8801; 2 mod 3. By an inductive argument, one can show: for g &#8805; 2 and 1 &#8804; e &#8804; g/2, there exists a partition r j=0 e j of g + 2 into r + 1 positive integers such that e j &#8801; 1 mod 3 and thus there exists a Z/3Z-cover of P 1 k having genus g and 3-rank 2r.</p></div></body>
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